###### Formulae

1. Speed, Time and Distance

Speed = (Distance/Time)

Time = (Distance/Speed)

Distance = (Speed x Time).

2. km per hr to m per sec conversion x km/hr = (x*5/18) m/sec.

3. m/sec to km/hr conversion x m/sec = (x *18/5) km/hr.

###### Exercise : Time and Distance MCQ Questions and Answers

**Question 1 **

Two cars ' X ' and ' Y' starts from Delhi to Mumbai. How much time does X take to reach Mumbai ? I The speed of car X is 40% of the speed of' Y'. II ' Y' took 16 hours to reach Mumbai.

A. |

B. |

C. |

D. |

**Correct Answer : C. If the question can be answered using both the statements together, but cant be answered using either statement alone. **

**Description :**

Both the statements are required to answer the question.

suppose the distance between Delhi to Mumbai is D km and speed of Y is V kmh-1

∴ D/V = 16

From (I),

speed of X is X = 40/100 x V = 2V/5

So time taken = D/(2V/5) = D/1 x 5/2V

∴ 5/2 D/V = 5/2 x 16 = 40 hours.

**Question 2 **

A train starts with a speed of 40 km/h with its speed increasing every hour by 10 km/h. In how many hours will it cover 185 km?

A. |

B. |

C. |

D. |

**Correct Answer : D. 3 (1/2) h **

**Description :**

No answer description available for this question. Let us discuss.

**Question 3 **

A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 54 min will be covered by B in :

A. |

B. |

C. |

D. |

**Correct Answer : A. 18 min **

**Description :**

Let C's speed = X kmph Then, B's speed = 3X kmph and A's speed = 6X kmph.

Ratio of the speed of A, B and C = 6X : 3X : X = 6 : 3 : 1

Ratio of time taken = 1/6 : 1/3 : 1 = 1 : 2 : 6

If C takes 6 min, then B takes 2 min

If C takes 54 min, then B takes (2/6) x 54 min. = 18 min.

**Question 4 **

A man covered a distance of 12 km in 90 min by cycle. How much distance will he cover in 3h, if he rides the cycle at a uniform speed?

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B. |

C. |

D. |

**Correct Answer : C. 24 km **

**Description :**

We know that. speed = Distance/Time

= 12/90 = (12×60)/90 = 8 km/h

Therefore, Distance covered in 3 h = Speed×Time = 8 × 3 = 24km

**Question 5 **

A train 150 m long is running with a speed of 54 km per hour. In what time will it pass a telegraph post?

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B. |

C. |

D. |

**Correct Answer : D. 10 s **

**Description :**

Step 1. Just change speed from km per hour to meter per second.

So 54 km / hour = 54*1000/(60*60)=54*5/18

=15 meter per second.

Step 2. Check train is passing through post or platform, bridge..

In this case, train is passing through telegraph post. So only train length is considered in passing through a telegraph post as length of telegraph post is negligible.

Step 3. Train length =150 meter

In one second, train cover 15 meter distance.

So in 10 second, it cover 150 meter distance and cross the telegraph post.

Answer 10 second.

**Question 6 **

How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr?

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B. |

C. |

D. |

**Correct Answer : D. 60 sec **

**Description :**

No answer description available for this question. Let us discuss.

**Question 7 **

Distance between Mumbai and London is 7200 km. If the speed of the boing 747 flying between the two places is 901 kph, how much approximate time in hrs will be required to cover the distance?

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B. |

C. |

D. |

**Correct Answer : B. 8 **

**Description :**

No answer description available for this question. Let us discuss.

**Question 8 **

A train is running with the speed of 45 km/hour. What is its speed in meter per second ?

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B. |

C. |

D. |

**Correct Answer : C. 12.5 **

**Description :**

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**Question 9 **

A man crosses a 1.5 Km long bridge in 5 minutes. What is his speed in Km/hr ?

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B. |

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D. |

**Correct Answer : D. 18 Km/hr **

**Description :**

speed in km/hr

=1.5/(1/12)

=18 km/hr

**Question 10 **

Two trains start at the same time from Aligarh and Delhi and proceed towards each other at 16km/hr and 21km/hr respectively, When they meet, it is found that one train has travelled 60 km more than th

A. |

B. |

C. |

D. |

**Correct Answer : D. 444km **

**Description :**

No answer description available for this question. Let us discuss.