Formulae
1. Age after n years = X + n
2. Age n years ago = X “ n
3. n times the age = nX
4. Age of y = (Ratio of y/Sum of ratios)× sum of ages
5. Age of y = (q/p+q)× A
Exercise : Ages MCQ Questions and Answers
1. The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
| A. |
| B. |
| C. |
| D. |
Correct Answer : D. 4 years
Description :
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.
View Answer
50/50
Workspace
Report
Discuss
2. The ratio of the present age of two brothers is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of their ages after 5 years?
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 3:5
Description :
Let the present ages of the two brothers be x and 2x years respectively.
Then, \( {(x - 5)} \over {(2x - 5)} \) = 1/3
=> 3(x - 5) = (2x - 5)
=> x = 10
Required ratio = (x + 5) : (2x + 5) = 15 : 25 = 3:5
View Answer
50/50
Workspace
Report
Discuss
3. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 10 years
Description :
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B's age = 2x = 10 years.
View Answer
50/50
Workspace
Report
Discuss
4. Ratio between the Present ages of A & B is 5 : 4. If the age of A, 3 years ago is 2 years more than the age of B 4 years hence then find their total age.
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 81 years
Description :
Given:
Ratio between the Present ages of A & B is 5 : 4
The age of A, 3 years ago is 2 years more than the age of B 4 years hence
Calculation:
Ratio between the Present ages of A & B is 5 : 4
⇒ Ages of A and B can be represented as 5x and 4x respectively
Now, the age of A, 3 years ago is 2 years more than the age of B 4 years hence
(5x - 3) = (4x + 4) + 2
⇒ x = 9
Total age of A and B = 5x + 4x = 9x
∴ Total age = 9 × 9 = 81 years
View Answer
50/50
Workspace
Report
Discuss
5. A year ago, Akash’s father’s age was 9 times that of Akash. After 3 years his father’s age will be 5 times that of his age. How old will Akash be next year?
| A. |
| B. |
| C. |
| D. |
Correct Answer : D. 6 years
Description :
Let one year ago age of Akash’s father be 9x and age of Akash be x.
According to the question
⇒ (9x + 4) / (x + 4) = 5/1
⇒ 9x + 4 = 5x + 20
⇒ x = 4
∴ Age of Akash one year ago = 4 years
Present age of Akash = 4 + 1 = 5 years
∴ Age of Akash next year = 5 + 1 = 6 years
Let the present age of Akash be x.
Let the present age of Akash father be y.
For 1 year ago
⇒ y - 1 = 9(x - 1)
⇒ y = 9x - 8
For after 3 years
⇒ y + 3 = 5(x + 3)
⇒ 9x - 8 + 3 = 5x + 15
⇒ 4x = 20
⇒ x = 5
Age of Akash next year = 5 + 1 = 6 years
∴ The age of Akash next year is 6 years.
View Answer
50/50
Workspace
Report
Discuss
6. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 20
Description :
Let the son's present age be x years. Then, man's present age = (x + 24) years.
∴ (x + 24) + 2 = 2(x + 2)
⇒ x + 26 = 2x + 4
⇒ x = 22.
View Answer
50/50
Workspace
Report
Discuss
7. The present age of A is 11 years more than the Present age of B. After 5 years, The age of A will be 4 times what B was 2 years ago. Find the Present age of A.
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 19
Description :
Given:
Present age of A is 11 years more than the Present age of B
After 5 years, The age of A will be 4 times of what B was 2 years ago
Calculation:
Present age A = B + 11
After 5 years,
A + 5 = 4 × (B - 2)
∵ A = B + 11 ,
B + 11 + 5 = 4 × (B - 2)
⇒ B + 16 = (4 × B) - 8
⇒ 3 × B = 24
∴ B = 8
⇒ A's present age = B + 11 = 8 + 11 = 19 years
View Answer
50/50
Workspace
Report
Discuss
8. The average age of a mother and her son is 45 yrs. The ratio of their ages is 3 : 2. Find the age of the son.
| A. |
| B. |
| C. |
| D. |
Correct Answer : C. 36 years
Description :
Given:
The average age of Mother and son = 45 yr
Mother and son’s age ratio = 3 : 2
Calculations:
Let the age of Mother be 3x.
Let the age of the son be 2x.
According to the question
⇒ \( {(3x + 2x)} \over 2 \) = 45
⇒ 5x = 90
⇒ x = 18
Son’s age = 2 × 18 = 36 yrs.
∴ Son’s age is 36 years.
As the average of the ages = 45 years
⇒ Sum of their ages = 45 × 2 = 90 years
⇒ Age of the son = \( 2 \over 5 \) × 90 = 36 years
View Answer
50/50
Workspace
Report
Discuss
9. Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X's present age in years?
| A. |
| B. |
| C. |
| D. |
Correct Answer : A. 35 years
Description :
Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X's present age = 5x = 35 years.
View Answer
50/50
Workspace
Report
Discuss
10. Six years ago, the ratio of ages of Kunal and Sagar was 6:5. Four years hence, the ratio of their ages will be 11:10. What is Sagar's age at present?
| A. |
| B. |
| C. |
| D. |
Correct Answer : B. 16 years
Description :
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, [(6x + 6) + 4] / [(5x + 6) + 4] = 11/10
10(6x + 10) = 11(5x + 10) => x = 2
Sagar's present age = (5x + 6) = 16 years.
View Answer
50/50
Workspace
Report
Discuss